(x^2+3)+(4+2x)=15

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Solution for (x^2+3)+(4+2x)=15 equation: 


Simplifying
(x2 + 3) + (4 + 2x) = 15

Reorder the terms:
(3 + x2) + (4 + 2x) = 15

Remove parenthesis around (3 + x2)
3 + x2 + (4 + 2x) = 15

Remove parenthesis around (4 + 2x)
3 + x2 + 4 + 2x = 15

Reorder the terms:
3 + 4 + 2x + x2 = 15

Combine like terms: 3 + 4 = 7
7 + 2x + x2 = 15

Solving
7 + 2x + x2 = 15

Solving for variable 'x'.

Reorder the terms:
7 + -15 + 2x + x2 = 15 + -15

Combine like terms: 7 + -15 = -8
-8 + 2x + x2 = 15 + -15

Combine like terms: 15 + -15 = 0
-8 + 2x + x2 = 0

Factor a trinomial.
(-4 + -1x)(2 + -1x) = 0


Subproblem 1
Set the factor '(-4 + -1x)' equal to zero and attempt to solve:

Simplifying
-4 + -1x = 0

Solving
-4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -1x = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -1x = 0 + 4
-1x = 0 + 4

Combine like terms: 0 + 4 = 4
-1x = 4

Divide each side by '-1'.
x = -4

Simplifying
x = -4

Subproblem 2
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2
Solution
x = {-4, 2}

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